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2020 MLB season: Don’t sleep on these teams

By Mitchell Vareldzis

MIAMI, FLORIDA - AUGUST 29: Joey Votto #19 of the Cincinnati Reds talks with Eugenio Suarez #7 against the Miami Marlins at Marlins Park on August 29, 2019 in Miami, Florida. (Photo by Michael Reaves/Getty Images)
MIAMI, FLORIDA - AUGUST 29: Joey Votto #19 of the Cincinnati Reds talks with Eugenio Suarez #7 against the Miami Marlins at Marlins Park on August 29, 2019 in Miami, Florida. (Photo by Michael Reaves/Getty Images) /
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(Photo by Ethan Miller/Getty Images) /

2020 MLB season: Don’t Sleep On These Teams

Cleveland Indians – 2019 record: 93-69

Wait, what? Your sleeper team is one that had 93 wins last year? What about the White Sox who did way more this offseason to improve the team?

Yes, I know. I’ve written about the White Sox before, on multiple occasions (here and here) and I am aware of how they could be deemed sleeper.

But they can’t be a sleeper team if everyone is high on their outlook this season.

The Cleveland Indians do not have a high outlook this season and have had their franchise shortstop as the subject of trade talks for the entire offseason. That is already an assumption they’re on the verge of a rebuild.

They traded away Corey Kluber and Trevor Bauer (at the deadline), but this team has plenty to move forward with including the guys behind them in the rotation in Shane Bieber and Mike Clevinger.

The offense is still threatening with the rise of Oscar Mercado and the resurgence of Carlos Santana. The Indians may have missed out on the postseason last year, but don’t count them out this year if they have a fully healthy team.

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